V Nagabhushanamma vs. Pradyumna P.S.

Court:High Court of Andhra Pradesh
Judge:Hon'ble K Manmadha Rao
Case Status:Disposed
Order Date:18 Nov 2022
CNR:APHC010606482022

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Order Issued After Hearing

Purpose:

Admission

Before:

Hon'ble K Manmadha Rao

Listed On:

18 Nov 2022

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Order Text

(SHOW CAUSE NOTICE BEFORE ADMISSION)

IN THE HIGH COURT OF ANDHRA PRADESH AT AMARAVATION

(Original Jurisdiction)

FRIDAY, THE EIGHTEENTH DAY OF NOVEMBER

TWO THOUSAND AND TWENTY TWO

:PRESENT:

THE HONOURABLE DR JUSTICE K MANMADHA RAO

CONTEMPT CASE NO: 5194 OF 2022

Between:

V Nagabhushanamma, W/o. Nagabhushanam, 56y, Junior Market Supervisor, Agricultural Market Committee, Mydukur, YSR Kadapa District.

Petitioner

AND

Sri Pradyumna P.S., I.A.S, Commissioner/Director of Marketing, Govt. of A.P., Guntur, Guntur District.

Contemnor

SD/- K.TATA RAO

DEPUTY REGISTRAR

SECTION OFFICER

$QB$

Whereas the petitioner has presented this Contempt case under Sections 10 to 12 of the Contempt of Courts Act, 1971, through her counsel Sri S Gopal Rao praying the High Court to punish the Contemnor/respondent herein, for willfully disobeying the orders dated 24.08.2022 passed by the High Court in W.P. No. 26861 of 2022, in the interest of justice.

Whereas the said case coming on for orders as to admission on this day and whereas the High Court, upon perusing the affidavit filed therein, and upon hearing the arguments of Sri S Gopal Rao Advocate for the petitioner, directed issuance of notice before admission to the respondent returnable by 16.12.2022 herein, to show cause as to why in the circumstances stated in the affidavit filed in support thereof, the said case should not be admitted.

Therefore, you namely

Sri Pradyumna P.S., I.A.S, Commissioner/Director of Marketing, Govt. of A.P., Guntur, Guntur District.

be and hereby are directed to show cause as to why this Contempt Case should not be admitted, either appearing in person or through Advocate duly instructed on 16-12-2022, to which date the case stands posted for hearing, failing which the said case will be heard and determined ex-parte.

$\mathcal{L} = \mathcal{L} = \mathcal{L}$ //TRUE COPY//

$P\left(\mathcal{X}\right) = P\left(\mathcal{X}\right) = P$

$\mathsf{To},$

,<br>1. The District Judge, Guntur, Guntur District. (By RPAD - in duplicate with a copy of petition and affidavit to serve on the sole respondent and to return to this Court before 16.12.2022).

  1. Sri Pradyumna P.S., I.A.S, Commissioner/Director of Marketing, Govt. of A.P.,

Guntur, Guntur District. (by RPAD - along with a copy of petition and affidavit) 3. One spare copy

NPC

HIGH COURT

Dr. KMR,J

DATED:18/11/2022

$\mathcal{L} = \mathcal{L} \mathcal{L}$

$\overline{\phantom{a}}$ $\mathcal{L}^{\mathcal{L}}$ $\mathbb{E} \left[ \mathbb{E}^{\infty} \right]$

$\begin{array}{cccccc} \bullet & & \bullet & & \bullet \ & \bullet & & \bullet & & \bullet \ \end{array}$

$\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}\frac{1}{\sqrt{2}}$ $\mathcal{L} = \mathcal{L}$

$\pi\approx 0$

Statistics

$\mathbb{E}[\mathcal{L}(\mathcal{L})]$

$\frac{1}{\sqrt{2}}$

$\mathcal{L} = \mathcal{L} \mathcal{L}$ $\mathcal{M}^{\mathcal{A}}(\mathcal{M}^{\mathcal{A}}(\mathcal{M}^{\mathcal{A}})) \to \mathcal{M}^{\mathcal{A}}(\mathcal{M}^{\mathcal{A}}(\mathcal{M}^{\mathcal{A}}))$ $\label{eq:1} \begin{array}{ccccccccccccccccccccccc} \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M} & \mathcal{M$

$\mathcal{L}^{\mathcal{L}^{\mathcal{L}}}{\mathcal{L}^{\mathcal{L}}} = \mathcal{L}^{\mathcal{L}^{\mathcal{L}}}{\mathcal{L}^{\mathcal{L}}}$

POST ON 16.12.2022.

NOTICE BEFORE ADMISSION

CC.No. 5194 of 2022

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Case History of Orders

Order(2) - 16 Dec 2022

Final Order

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Order(1) - 18 Nov 2022

Interim Order

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